5(3z-1)+3(z+2)=4(2+1)

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Solution for 5(3z-1)+3(z+2)=4(2+1) equation:


Simplifying
5(3z + -1) + 3(z + 2) = 4(2 + 1)

Reorder the terms:
5(-1 + 3z) + 3(z + 2) = 4(2 + 1)
(-1 * 5 + 3z * 5) + 3(z + 2) = 4(2 + 1)
(-5 + 15z) + 3(z + 2) = 4(2 + 1)

Reorder the terms:
-5 + 15z + 3(2 + z) = 4(2 + 1)
-5 + 15z + (2 * 3 + z * 3) = 4(2 + 1)
-5 + 15z + (6 + 3z) = 4(2 + 1)

Reorder the terms:
-5 + 6 + 15z + 3z = 4(2 + 1)

Combine like terms: -5 + 6 = 1
1 + 15z + 3z = 4(2 + 1)

Combine like terms: 15z + 3z = 18z
1 + 18z = 4(2 + 1)

Combine like terms: 2 + 1 = 3
1 + 18z = 4(3)

Multiply 4 * 3
1 + 18z = 12

Solving
1 + 18z = 12

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 18z = 12 + -1

Combine like terms: 1 + -1 = 0
0 + 18z = 12 + -1
18z = 12 + -1

Combine like terms: 12 + -1 = 11
18z = 11

Divide each side by '18'.
z = 0.6111111111

Simplifying
z = 0.6111111111

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