5(3z-1)-3(z+1)=9(z+1)

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Solution for 5(3z-1)-3(z+1)=9(z+1) equation: 



5(3z-1)-3(z+1)=9(z+1)

We move all terms to the left:

5(3z-1)-3(z+1)-(9(z+1))=0

We multiply parentheses

15z-3z-(9(z+1))-5-3=0



We calculate terms in parentheses: -(9(z+1)), so:

9(z+1)

We multiply parentheses

9z+9

Back to the equation:

-(9z+9)



We add all the numbers together, and all the variables

12z-(9z+9)-8=0

We get rid of parentheses

12z-9z-9-8=0

We add all the numbers together, and all the variables

3z-17=0

We move all terms containing z to the left, all other terms to the right

3z=17

z=17/3

z=5+2/3

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