5(3z-1)-3(z+2)=2(2+1)

Solution for 5(3z-1)-3(z+2)=2(2+1) equation:

Simplifying
5(3z + -1) + -3(z + 2) = 2(2 + 1)

Reorder the terms:
5(-1 + 3z) + -3(z + 2) = 2(2 + 1)
(-1 * 5 + 3z * 5) + -3(z + 2) = 2(2 + 1)
(-5 + 15z) + -3(z + 2) = 2(2 + 1)

Reorder the terms:
-5 + 15z + -3(2 + z) = 2(2 + 1)
-5 + 15z + (2 * -3 + z * -3) = 2(2 + 1)
-5 + 15z + (-6 + -3z) = 2(2 + 1)

Reorder the terms:
-5 + -6 + 15z + -3z = 2(2 + 1)

Combine like terms: -5 + -6 = -11
-11 + 15z + -3z = 2(2 + 1)

Combine like terms: 15z + -3z = 12z
-11 + 12z = 2(2 + 1)

Combine like terms: 2 + 1 = 3
-11 + 12z = 2(3)

Multiply 2 * 3
-11 + 12z = 6

Solving
-11 + 12z = 6

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 12z = 6 + 11

Combine like terms: -11 + 11 = 0
0 + 12z = 6 + 11
12z = 6 + 11

Combine like terms: 6 + 11 = 17
12z = 17

Divide each side by '12'.
z = 1.416666667

Simplifying
z = 1.416666667