5(3z-1)-3(z+4)=2(z+1)

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Solution for 5(3z-1)-3(z+4)=2(z+1) equation:


Simplifying
5(3z + -1) + -3(z + 4) = 2(z + 1)

Reorder the terms:
5(-1 + 3z) + -3(z + 4) = 2(z + 1)
(-1 * 5 + 3z * 5) + -3(z + 4) = 2(z + 1)
(-5 + 15z) + -3(z + 4) = 2(z + 1)

Reorder the terms:
-5 + 15z + -3(4 + z) = 2(z + 1)
-5 + 15z + (4 * -3 + z * -3) = 2(z + 1)
-5 + 15z + (-12 + -3z) = 2(z + 1)

Reorder the terms:
-5 + -12 + 15z + -3z = 2(z + 1)

Combine like terms: -5 + -12 = -17
-17 + 15z + -3z = 2(z + 1)

Combine like terms: 15z + -3z = 12z
-17 + 12z = 2(z + 1)

Reorder the terms:
-17 + 12z = 2(1 + z)
-17 + 12z = (1 * 2 + z * 2)
-17 + 12z = (2 + 2z)

Solving
-17 + 12z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-17 + 12z + -2z = 2 + 2z + -2z

Combine like terms: 12z + -2z = 10z
-17 + 10z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-17 + 10z = 2 + 0
-17 + 10z = 2

Add '17' to each side of the equation.
-17 + 17 + 10z = 2 + 17

Combine like terms: -17 + 17 = 0
0 + 10z = 2 + 17
10z = 2 + 17

Combine like terms: 2 + 17 = 19
10z = 19

Divide each side by '10'.
z = 1.9

Simplifying
z = 1.9

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