5(3z-1)-3(z+4)=4(z+1)

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Solution for 5(3z-1)-3(z+4)=4(z+1) equation:


Simplifying
5(3z + -1) + -3(z + 4) = 4(z + 1)

Reorder the terms:
5(-1 + 3z) + -3(z + 4) = 4(z + 1)
(-1 * 5 + 3z * 5) + -3(z + 4) = 4(z + 1)
(-5 + 15z) + -3(z + 4) = 4(z + 1)

Reorder the terms:
-5 + 15z + -3(4 + z) = 4(z + 1)
-5 + 15z + (4 * -3 + z * -3) = 4(z + 1)
-5 + 15z + (-12 + -3z) = 4(z + 1)

Reorder the terms:
-5 + -12 + 15z + -3z = 4(z + 1)

Combine like terms: -5 + -12 = -17
-17 + 15z + -3z = 4(z + 1)

Combine like terms: 15z + -3z = 12z
-17 + 12z = 4(z + 1)

Reorder the terms:
-17 + 12z = 4(1 + z)
-17 + 12z = (1 * 4 + z * 4)
-17 + 12z = (4 + 4z)

Solving
-17 + 12z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-17 + 12z + -4z = 4 + 4z + -4z

Combine like terms: 12z + -4z = 8z
-17 + 8z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-17 + 8z = 4 + 0
-17 + 8z = 4

Add '17' to each side of the equation.
-17 + 17 + 8z = 4 + 17

Combine like terms: -17 + 17 = 0
0 + 8z = 4 + 17
8z = 4 + 17

Combine like terms: 4 + 17 = 21
8z = 21

Divide each side by '8'.
z = 2.625

Simplifying
z = 2.625

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