5(3z-1)-4(z+2)=6(z+1)

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Solution for 5(3z-1)-4(z+2)=6(z+1) equation:


Simplifying
5(3z + -1) + -4(z + 2) = 6(z + 1)

Reorder the terms:
5(-1 + 3z) + -4(z + 2) = 6(z + 1)
(-1 * 5 + 3z * 5) + -4(z + 2) = 6(z + 1)
(-5 + 15z) + -4(z + 2) = 6(z + 1)

Reorder the terms:
-5 + 15z + -4(2 + z) = 6(z + 1)
-5 + 15z + (2 * -4 + z * -4) = 6(z + 1)
-5 + 15z + (-8 + -4z) = 6(z + 1)

Reorder the terms:
-5 + -8 + 15z + -4z = 6(z + 1)

Combine like terms: -5 + -8 = -13
-13 + 15z + -4z = 6(z + 1)

Combine like terms: 15z + -4z = 11z
-13 + 11z = 6(z + 1)

Reorder the terms:
-13 + 11z = 6(1 + z)
-13 + 11z = (1 * 6 + z * 6)
-13 + 11z = (6 + 6z)

Solving
-13 + 11z = 6 + 6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6z' to each side of the equation.
-13 + 11z + -6z = 6 + 6z + -6z

Combine like terms: 11z + -6z = 5z
-13 + 5z = 6 + 6z + -6z

Combine like terms: 6z + -6z = 0
-13 + 5z = 6 + 0
-13 + 5z = 6

Add '13' to each side of the equation.
-13 + 13 + 5z = 6 + 13

Combine like terms: -13 + 13 = 0
0 + 5z = 6 + 13
5z = 6 + 13

Combine like terms: 6 + 13 = 19
5z = 19

Divide each side by '5'.
z = 3.8

Simplifying
z = 3.8

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