5(3z-1)-5(z+4)=4(z=1)

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Solution for 5(3z-1)-5(z+4)=4(z=1) equation: 



5(3z-1)-5(z+4)=4(z=1)

We move all terms to the left:

5(3z-1)-5(z+4)-(4(z)=0

We multiply parentheses

15z-5z-(4z-5-20=0

We add all the numbers together, and all the variables

10z-(4z-5-20=0

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