5(3z-2)=-16(7-z)

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Solution for 5(3z-2)=-16(7-z) equation: 



5(3z-2)=-16(7-z)

We move all terms to the left:

5(3z-2)-(-16(7-z))=0

We add all the numbers together, and all the variables

5(3z-2)-(-16(-1z+7))=0

We multiply parentheses

15z-(-16(-1z+7))-10=0



We calculate terms in parentheses: -(-16(-1z+7)), so:

-16(-1z+7)

We multiply parentheses

16z-112

Back to the equation:

-(16z-112)



We get rid of parentheses

15z-16z+112-10=0

We add all the numbers together, and all the variables

-1z+102=0

We move all terms containing z to the left, all other terms to the right

-z=-102

z=-102/-1

z=+102

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