5(4+2)+p=10

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Solution for 5(4+2)+p=10 equation:



5(4+2)+p=10
We move all terms to the left:
5(4+2)+p-(10)=0
determiningTheFunctionDomain p-10+5(4+2)=0
We add all the numbers together, and all the variables
p-10+56=0
We add all the numbers together, and all the variables
p+46=0
We move all terms containing p to the left, all other terms to the right
p=-46

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