5(4+2)+p=10

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Solution for 5(4+2)+p=10 equation: 



5(4+2)+p=10

We move all terms to the left:

5(4+2)+p-(10)=0

determiningTheFunctionDomain
p-10+5(4+2)=0

We add all the numbers together, and all the variables

p-10+56=0

We add all the numbers together, and all the variables

p+46=0

We move all terms containing p to the left, all other terms to the right

p=-46

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