5(4+2m)-2=8(1+m)

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Solution for 5(4+2m)-2=8(1+m) equation: 



5(4+2m)-2=8(1+m)

We move all terms to the left:

5(4+2m)-2-(8(1+m))=0

We add all the numbers together, and all the variables

5(2m+4)-(8(m+1))-2=0

We multiply parentheses

10m-(8(m+1))+20-2=0



We calculate terms in parentheses: -(8(m+1)), so:

8(m+1)

We multiply parentheses

8m+8

Back to the equation:

-(8m+8)



We add all the numbers together, and all the variables

10m-(8m+8)+18=0

We get rid of parentheses

10m-8m-8+18=0

We add all the numbers together, and all the variables

2m+10=0

We move all terms containing m to the left, all other terms to the right

2m=-10

m=-10/2

m=-5

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