5(4+2x)-(8x-12)-(68)=0

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Solution for 5(4+2x)-(8x-12)-(68)=0 equation: 



5(4+2x)-(8x-12)-(68)=0

We add all the numbers together, and all the variables

5(2x+4)-(8x-12)-68=0

We multiply parentheses

10x-(8x-12)+20-68=0

We get rid of parentheses

10x-8x+12+20-68=0

We add all the numbers together, and all the variables

2x-36=0

We move all terms containing x to the left, all other terms to the right

2x=36

x=36/2

x=18

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