5(4+2x)-8x-12)=68

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Solution for 5(4+2x)-8x-12)=68 equation: 



5(4+2x)-8x-12)=68

We move all terms to the left:

5(4+2x)-8x-12)-(68)=0

We add all the numbers together, and all the variables

5(2x+4)-8x-12)-68=0

We add all the numbers together, and all the variables

-8x+5(2x+4)=0

We multiply parentheses

-8x+10x+20=0

We add all the numbers together, and all the variables

2x+20=0

We move all terms containing x to the left, all other terms to the right

2x=-20

x=-20/2

x=-10

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