5(4+3)=4(7x-5)+3(9-2x)

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Solution for 5(4+3)=4(7x-5)+3(9-2x) equation: 



5(4+3)=4(7x-5)+3(9-2x)

We move all terms to the left:

5(4+3)-(4(7x-5)+3(9-2x))=0

We add all the numbers together, and all the variables

-(4(7x-5)+3(-2x+9))+57=0



We calculate terms in parentheses: -(4(7x-5)+3(-2x+9)), so:

4(7x-5)+3(-2x+9)

We multiply parentheses

28x-6x-20+27

We add all the numbers together, and all the variables

22x+7

Back to the equation:

-(22x+7)



We get rid of parentheses

-22x-7+57=0

We add all the numbers together, and all the variables

-22x+50=0

We move all terms containing x to the left, all other terms to the right

-22x=-50

x=-50/-22

x=2+3/11

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