5(4+3p+1)+4(p+1)=

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Solution for 5(4+3p+1)+4(p+1)= equation:


Simplifying
5(4 + 3p + 1) + 4(p + 1) = 0

Reorder the terms:
5(4 + 1 + 3p) + 4(p + 1) = 0

Combine like terms: 4 + 1 = 5
5(5 + 3p) + 4(p + 1) = 0
(5 * 5 + 3p * 5) + 4(p + 1) = 0
(25 + 15p) + 4(p + 1) = 0

Reorder the terms:
25 + 15p + 4(1 + p) = 0
25 + 15p + (1 * 4 + p * 4) = 0
25 + 15p + (4 + 4p) = 0

Reorder the terms:
25 + 4 + 15p + 4p = 0

Combine like terms: 25 + 4 = 29
29 + 15p + 4p = 0

Combine like terms: 15p + 4p = 19p
29 + 19p = 0

Solving
29 + 19p = 0

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-29' to each side of the equation.
29 + -29 + 19p = 0 + -29

Combine like terms: 29 + -29 = 0
0 + 19p = 0 + -29
19p = 0 + -29

Combine like terms: 0 + -29 = -29
19p = -29

Divide each side by '19'.
p = -1.526315789

Simplifying
p = -1.526315789

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