5(4+6x)=320

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Solution for 5(4+6x)=320 equation: 



5(4+6x)=320

We move all terms to the left:

5(4+6x)-(320)=0

We add all the numbers together, and all the variables

5(6x+4)-320=0

We multiply parentheses

30x+20-320=0

We add all the numbers together, and all the variables

30x-300=0

We move all terms containing x to the left, all other terms to the right

30x=300

x=300/30

x=10

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