5(4+7x)-20=5(22+2x)+2x-3

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Solution for 5(4+7x)-20=5(22+2x)+2x-3 equation: 



5(4+7x)-20=5(22+2x)+2x-3

We move all terms to the left:

5(4+7x)-20-(5(22+2x)+2x-3)=0

We add all the numbers together, and all the variables

5(7x+4)-(5(2x+22)+2x-3)-20=0

We multiply parentheses

35x-(5(2x+22)+2x-3)+20-20=0



We calculate terms in parentheses: -(5(2x+22)+2x-3), so:

5(2x+22)+2x-3

We add all the numbers together, and all the variables

2x+5(2x+22)-3

We multiply parentheses

2x+10x+110-3

We add all the numbers together, and all the variables

12x+107

Back to the equation:

-(12x+107)



We add all the numbers together, and all the variables

35x-(12x+107)=0

We get rid of parentheses

35x-12x-107=0

We add all the numbers together, and all the variables

23x-107=0

We move all terms containing x to the left, all other terms to the right

23x=107

x=107/23

x=4+15/23

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