5(4+a)=(3a-1)-9

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Solution for 5(4+a)=(3a-1)-9 equation: 



5(4+a)=(3a-1)-9

We move all terms to the left:

5(4+a)-((3a-1)-9)=0

We add all the numbers together, and all the variables

5(a+4)-((3a-1)-9)=0

We multiply parentheses

5a-((3a-1)-9)+20=0



We calculate terms in parentheses: -((3a-1)-9), so:

(3a-1)-9

We get rid of parentheses

3a-1-9

We add all the numbers together, and all the variables

3a-10

Back to the equation:

-(3a-10)



We get rid of parentheses

5a-3a+10+20=0

We add all the numbers together, and all the variables

2a+30=0

We move all terms containing a to the left, all other terms to the right

2a=-30

a=-30/2

a=-15

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