5(4+c)+1=2(3+c)

Solution for 5(4+c)+1=2(3+c) equation:

Simplifying
5(4 + c) + 1 = 2(3 + c)
(4 * 5 + c * 5) + 1 = 2(3 + c)
(20 + 5c) + 1 = 2(3 + c)

Reorder the terms:
20 + 1 + 5c = 2(3 + c)

Combine like terms: 20 + 1 = 21
21 + 5c = 2(3 + c)
21 + 5c = (3 * 2 + c * 2)
21 + 5c = (6 + 2c)

Solving
21 + 5c = 6 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
21 + 5c + -2c = 6 + 2c + -2c

Combine like terms: 5c + -2c = 3c
21 + 3c = 6 + 2c + -2c

Combine like terms: 2c + -2c = 0
21 + 3c = 6 + 0
21 + 3c = 6

Add '-21' to each side of the equation.
21 + -21 + 3c = 6 + -21

Combine like terms: 21 + -21 = 0
0 + 3c = 6 + -21
3c = 6 + -21

Combine like terms: 6 + -21 = -15
3c = -15

Divide each side by '3'.
c = -5

Simplifying
c = -5