5(4+c)=20+

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Solution for 5(4+c)=20+ equation: 



5(4+c)=20+

We move all terms to the left:

5(4+c)-(20+)=0

We add all the numbers together, and all the variables

5(c+4)-0=0

We add all the numbers together, and all the variables

5(c+4)=0

We multiply parentheses

5c+20=0

We move all terms containing c to the left, all other terms to the right

5c=-20

c=-20/5

c=-4

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