5(4+d)-2(d+3)=20

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Solution for 5(4+d)-2(d+3)=20 equation: 



5(4+d)-2(d+3)=20

We move all terms to the left:

5(4+d)-2(d+3)-(20)=0

We add all the numbers together, and all the variables

5(d+4)-2(d+3)-20=0

We multiply parentheses

5d-2d+20-6-20=0

We add all the numbers together, and all the variables

3d-6=0

We move all terms containing d to the left, all other terms to the right

3d=6

d=6/3

d=2

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