5(4+r)=1/2(40+10r)

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Solution for 5(4+r)=1/2(40+10r) equation: 


r in (-oo:+oo)

5*(r+4) = (1/2)*(10*r+40) // - (1/2)*(10*r+40)

5*(r+4)-((1/2)*(10*r+40)) = 0

5*(r+4)+(-1/2)*(10*r+40) = 0

5*(r+4)-1/2*(10*r+40) = 0

5*(r+4)-1/2*(10*r+40) = 0

0 = 0

0 = 0

r belongs to the empty set

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