5(4+r)=50(40+10r)

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Solution for 5(4+r)=50(40+10r) equation: 



5(4+r)=50(40+10r)

We move all terms to the left:

5(4+r)-(50(40+10r))=0

We add all the numbers together, and all the variables

5(r+4)-(50(10r+40))=0

We multiply parentheses

5r-(50(10r+40))+20=0



We calculate terms in parentheses: -(50(10r+40)), so:

50(10r+40)

We multiply parentheses

500r+2000

Back to the equation:

-(500r+2000)



We get rid of parentheses

5r-500r-2000+20=0

We add all the numbers together, and all the variables

-495r-1980=0

We move all terms containing r to the left, all other terms to the right

-495r=1980

r=1980/-495

r=-4

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