5(4+y)=2y+20+3y

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Solution for 5(4+y)=2y+20+3y equation:


Simplifying
5(4 + y) = 2y + 20 + 3y
(4 * 5 + y * 5) = 2y + 20 + 3y
(20 + 5y) = 2y + 20 + 3y

Reorder the terms:
20 + 5y = 20 + 2y + 3y

Combine like terms: 2y + 3y = 5y
20 + 5y = 20 + 5y

Add '-20' to each side of the equation.
20 + -20 + 5y = 20 + -20 + 5y

Combine like terms: 20 + -20 = 0
0 + 5y = 20 + -20 + 5y
5y = 20 + -20 + 5y

Combine like terms: 20 + -20 = 0
5y = 0 + 5y
5y = 5y

Add '-5y' to each side of the equation.
5y + -5y = 5y + -5y

Combine like terms: 5y + -5y = 0
0 = 5y + -5y

Combine like terms: 5y + -5y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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