5(4-1)=2(r-4)-6

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Solution for 5(4-1)=2(r-4)-6 equation: 



5(4-1)=2(r-4)-6

We move all terms to the left:

5(4-1)-(2(r-4)-6)=0

We add all the numbers together, and all the variables

-(2(r-4)-6)+53=0



We calculate terms in parentheses: -(2(r-4)-6), so:

2(r-4)-6

We multiply parentheses

2r-8-6

We add all the numbers together, and all the variables

2r-14

Back to the equation:

-(2r-14)



We get rid of parentheses

-2r+14+53=0

We add all the numbers together, and all the variables

-2r+67=0

We move all terms containing r to the left, all other terms to the right

-2r=-67

r=-67/-2

r=33+1/2

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