5(4-2a)=-5(1-3a)

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Solution for 5(4-2a)=-5(1-3a) equation: 



5(4-2a)=-5(1-3a)

We move all terms to the left:

5(4-2a)-(-5(1-3a))=0

We add all the numbers together, and all the variables

5(-2a+4)-(-5(-3a+1))=0

We multiply parentheses

-10a-(-5(-3a+1))+20=0



We calculate terms in parentheses: -(-5(-3a+1)), so:

-5(-3a+1)

We multiply parentheses

15a-5

Back to the equation:

-(15a-5)



We get rid of parentheses

-10a-15a+5+20=0

We add all the numbers together, and all the variables

-25a+25=0

We move all terms containing a to the left, all other terms to the right

-25a=-25

a=-25/-25

a=1

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