5(4-2x)=8(2x-1)

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Solution for 5(4-2x)=8(2x-1) equation: 



5(4-2x)=8(2x-1)

We move all terms to the left:

5(4-2x)-(8(2x-1))=0

We add all the numbers together, and all the variables

5(-2x+4)-(8(2x-1))=0

We multiply parentheses

-10x-(8(2x-1))+20=0



We calculate terms in parentheses: -(8(2x-1)), so:

8(2x-1)

We multiply parentheses

16x-8

Back to the equation:

-(16x-8)



We get rid of parentheses

-10x-16x+8+20=0

We add all the numbers together, and all the variables

-26x+28=0

We move all terms containing x to the left, all other terms to the right

-26x=-28

x=-28/-26

x=1+1/13

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