5(4-6x)+30=10(7x-5)

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Solution for 5(4-6x)+30=10(7x-5) equation: 



5(4-6x)+30=10(7x-5)

We move all terms to the left:

5(4-6x)+30-(10(7x-5))=0

We add all the numbers together, and all the variables

5(-6x+4)-(10(7x-5))+30=0

We multiply parentheses

-30x-(10(7x-5))+20+30=0



We calculate terms in parentheses: -(10(7x-5)), so:

10(7x-5)

We multiply parentheses

70x-50

Back to the equation:

-(70x-50)



We add all the numbers together, and all the variables

-30x-(70x-50)+50=0

We get rid of parentheses

-30x-70x+50+50=0

We add all the numbers together, and all the variables

-100x+100=0

We move all terms containing x to the left, all other terms to the right

-100x=-100

x=-100/-100

x=1

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