5(4-c)/4=-4(2c+1)/7

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Solution for 5(4-c)/4=-4(2c+1)/7 equation: 



5(4-c)/4=-4(2c+1)/7

We move all terms to the left:

5(4-c)/4-(-4(2c+1)/7)=0

We add all the numbers together, and all the variables

5(-1c+4)/4-(-4(2c+1)/7)=0

We calculate fractions


(-5c)/()+(-(-4(2c+1)*4)/()=0



We calculate terms in parentheses: +(-(-4(2c+1)*4)/(), so:

-(-4(2c+1)*4)/(

We multiply all the terms by the denominator


-(-4(2c+1)*4)



We calculate terms in parentheses: -(-4(2c+1)*4), so:

-4(2c+1)*4

We multiply parentheses

-32c-16

Back to the equation:

-(-32c-16)



We get rid of parentheses

32c+16

Back to the equation:

+(32c+16)



We get rid of parentheses

(-5c)/()+32c+16=0

We multiply all the terms by the denominator


(-5c)+32c*()+16*()=0

We add all the numbers together, and all the variables

(-5c)+32c*()=0

We get rid of parentheses

-5c+32c*()=0

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