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5(4-x)=2(10-x)
We move all terms to the left:
5(4-x)-(2(10-x))=0
We add all the numbers together, and all the variables
5(-1x+4)-(2(-1x+10))=0
We multiply parentheses
-5x-(2(-1x+10))+20=0
We calculate terms in parentheses: -(2(-1x+10)), so:We get rid of parentheses
2(-1x+10)
We multiply parentheses
-2x+20
Back to the equation:
-(-2x+20)
-5x+2x-20+20=0
We add all the numbers together, and all the variables
-3x=0
x=0/-3
x=0
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