5(4-y)-4(y+2)=12

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Solution for 5(4-y)-4(y+2)=12 equation:


Simplifying
5(4 + -1y) + -4(y + 2) = 12
(4 * 5 + -1y * 5) + -4(y + 2) = 12
(20 + -5y) + -4(y + 2) = 12

Reorder the terms:
20 + -5y + -4(2 + y) = 12
20 + -5y + (2 * -4 + y * -4) = 12
20 + -5y + (-8 + -4y) = 12

Reorder the terms:
20 + -8 + -5y + -4y = 12

Combine like terms: 20 + -8 = 12
12 + -5y + -4y = 12

Combine like terms: -5y + -4y = -9y
12 + -9y = 12

Add '-12' to each side of the equation.
12 + -12 + -9y = 12 + -12

Combine like terms: 12 + -12 = 0
0 + -9y = 12 + -12
-9y = 12 + -12

Combine like terms: 12 + -12 = 0
-9y = 0

Solving
-9y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-9'.
y = 0

Simplifying
y = 0

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