5(4a+5)=(a-4)

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Solution for 5(4a+5)=(a-4) equation: 



5(4a+5)=(a-4)

We move all terms to the left:

5(4a+5)-((a-4))=0

We multiply parentheses

20a-((a-4))+25=0



We calculate terms in parentheses: -((a-4)), so:

(a-4)

We get rid of parentheses

a-4

Back to the equation:

-(a-4)



We get rid of parentheses

20a-a+4+25=0

We add all the numbers together, and all the variables

19a+29=0

We move all terms containing a to the left, all other terms to the right

19a=-29

a=-29/19

a=-1+10/19

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