5(4b-2)=-3(2b+64)

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Solution for 5(4b-2)=-3(2b+64) equation: 



5(4b-2)=-3(2b+64)

We move all terms to the left:

5(4b-2)-(-3(2b+64))=0

We multiply parentheses

20b-(-3(2b+64))-10=0



We calculate terms in parentheses: -(-3(2b+64)), so:

-3(2b+64)

We multiply parentheses

-6b-192

Back to the equation:

-(-6b-192)



We get rid of parentheses

20b+6b+192-10=0

We add all the numbers together, and all the variables

26b+182=0

We move all terms containing b to the left, all other terms to the right

26b=-182

b=-182/26

b=-7

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