5(4c+1)=5(c+13)

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Solution for 5(4c+1)=5(c+13) equation:


Simplifying
5(4c + 1) = 5(c + 13)

Reorder the terms:
5(1 + 4c) = 5(c + 13)
(1 * 5 + 4c * 5) = 5(c + 13)
(5 + 20c) = 5(c + 13)

Reorder the terms:
5 + 20c = 5(13 + c)
5 + 20c = (13 * 5 + c * 5)
5 + 20c = (65 + 5c)

Solving
5 + 20c = 65 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
5 + 20c + -5c = 65 + 5c + -5c

Combine like terms: 20c + -5c = 15c
5 + 15c = 65 + 5c + -5c

Combine like terms: 5c + -5c = 0
5 + 15c = 65 + 0
5 + 15c = 65

Add '-5' to each side of the equation.
5 + -5 + 15c = 65 + -5

Combine like terms: 5 + -5 = 0
0 + 15c = 65 + -5
15c = 65 + -5

Combine like terms: 65 + -5 = 60
15c = 60

Divide each side by '15'.
c = 4

Simplifying
c = 4

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