5(4c+3)=6(3c+2)-1

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Solution for 5(4c+3)=6(3c+2)-1 equation:


Simplifying
5(4c + 3) = 6(3c + 2) + -1

Reorder the terms:
5(3 + 4c) = 6(3c + 2) + -1
(3 * 5 + 4c * 5) = 6(3c + 2) + -1
(15 + 20c) = 6(3c + 2) + -1

Reorder the terms:
15 + 20c = 6(2 + 3c) + -1
15 + 20c = (2 * 6 + 3c * 6) + -1
15 + 20c = (12 + 18c) + -1

Reorder the terms:
15 + 20c = 12 + -1 + 18c

Combine like terms: 12 + -1 = 11
15 + 20c = 11 + 18c

Solving
15 + 20c = 11 + 18c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-18c' to each side of the equation.
15 + 20c + -18c = 11 + 18c + -18c

Combine like terms: 20c + -18c = 2c
15 + 2c = 11 + 18c + -18c

Combine like terms: 18c + -18c = 0
15 + 2c = 11 + 0
15 + 2c = 11

Add '-15' to each side of the equation.
15 + -15 + 2c = 11 + -15

Combine like terms: 15 + -15 = 0
0 + 2c = 11 + -15
2c = 11 + -15

Combine like terms: 11 + -15 = -4
2c = -4

Divide each side by '2'.
c = -2

Simplifying
c = -2

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