5(4c-3)=-35+6c

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Solution for 5(4c-3)=-35+6c equation:



5(4c-3)=-35+6c
We move all terms to the left:
5(4c-3)-(-35+6c)=0
We add all the numbers together, and all the variables
5(4c-3)-(6c-35)=0
We multiply parentheses
20c-(6c-35)-15=0
We get rid of parentheses
20c-6c+35-15=0
We add all the numbers together, and all the variables
14c+20=0
We move all terms containing c to the left, all other terms to the right
14c=-20
c=-20/14
c=-1+3/7

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