5(4c-4)=5(3c+3)

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Solution for 5(4c-4)=5(3c+3) equation: 



5(4c-4)=5(3c+3)

We move all terms to the left:

5(4c-4)-(5(3c+3))=0

We multiply parentheses

20c-(5(3c+3))-20=0



We calculate terms in parentheses: -(5(3c+3)), so:

5(3c+3)

We multiply parentheses

15c+15

Back to the equation:

-(15c+15)



We get rid of parentheses

20c-15c-15-20=0

We add all the numbers together, and all the variables

5c-35=0

We move all terms containing c to the left, all other terms to the right

5c=35

c=35/5

c=7

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