5(4f+3)=2(5f-1)

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Solution for 5(4f+3)=2(5f-1) equation: 



5(4f+3)=2(5f-1)

We move all terms to the left:

5(4f+3)-(2(5f-1))=0

We multiply parentheses

20f-(2(5f-1))+15=0



We calculate terms in parentheses: -(2(5f-1)), so:

2(5f-1)

We multiply parentheses

10f-2

Back to the equation:

-(10f-2)



We get rid of parentheses

20f-10f+2+15=0

We add all the numbers together, and all the variables

10f+17=0

We move all terms containing f to the left, all other terms to the right

10f=-17

f=-17/10

f=-1+7/10

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