5(4f-7)=32

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Solution for 5(4f-7)=32 equation: 



5(4f-7)=32

We move all terms to the left:

5(4f-7)-(32)=0

We multiply parentheses

20f-35-32=0

We add all the numbers together, and all the variables

20f-67=0

We move all terms containing f to the left, all other terms to the right

20f=67

f=67/20

f=3+7/20

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