5(4g+12)=28

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Solution for 5(4g+12)=28 equation: 



5(4g+12)=28

We move all terms to the left:

5(4g+12)-(28)=0

We multiply parentheses

20g+60-28=0

We add all the numbers together, and all the variables

20g+32=0

We move all terms containing g to the left, all other terms to the right

20g=-32

g=-32/20

g=-1+3/5

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