5(4g-12)=28

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Solution for 5(4g-12)=28 equation: 



5(4g-12)=28

We move all terms to the left:

5(4g-12)-(28)=0

We multiply parentheses

20g-60-28=0

We add all the numbers together, and all the variables

20g-88=0

We move all terms containing g to the left, all other terms to the right

20g=88

g=88/20

g=4+2/5

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