5(4g-12)=48

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Solution for 5(4g-12)=48 equation: 



5(4g-12)=48

We move all terms to the left:

5(4g-12)-(48)=0

We multiply parentheses

20g-60-48=0

We add all the numbers together, and all the variables

20g-108=0

We move all terms containing g to the left, all other terms to the right

20g=108

g=108/20

g=5+2/5

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