5(4m+5)+3=128

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Solution for 5(4m+5)+3=128 equation: 



5(4m+5)+3=128

We move all terms to the left:

5(4m+5)+3-(128)=0

We add all the numbers together, and all the variables

5(4m+5)-125=0

We multiply parentheses

20m+25-125=0

We add all the numbers together, and all the variables

20m-100=0

We move all terms containing m to the left, all other terms to the right

20m=100

m=100/20

m=5

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