5(4n+4)=2(5n-4)+11n

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Solution for 5(4n+4)=2(5n-4)+11n equation: 



5(4n+4)=2(5n-4)+11n

We move all terms to the left:

5(4n+4)-(2(5n-4)+11n)=0

We multiply parentheses

20n-(2(5n-4)+11n)+20=0



We calculate terms in parentheses: -(2(5n-4)+11n), so:

2(5n-4)+11n

We add all the numbers together, and all the variables

11n+2(5n-4)

We multiply parentheses

11n+10n-8

We add all the numbers together, and all the variables

21n-8

Back to the equation:

-(21n-8)



We get rid of parentheses

20n-21n+8+20=0

We add all the numbers together, and all the variables

-1n+28=0

We move all terms containing n to the left, all other terms to the right

-n=-28

n=-28/-1

n=+28

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