5(4q-6)-6(2q-3)=4(1+q)

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Solution for 5(4q-6)-6(2q-3)=4(1+q) equation: 



5(4q-6)-6(2q-3)=4(1+q)

We move all terms to the left:

5(4q-6)-6(2q-3)-(4(1+q))=0

We add all the numbers together, and all the variables

5(4q-6)-6(2q-3)-(4(q+1))=0

We multiply parentheses

20q-12q-(4(q+1))-30+18=0



We calculate terms in parentheses: -(4(q+1)), so:

4(q+1)

We multiply parentheses

4q+4

Back to the equation:

-(4q+4)



We add all the numbers together, and all the variables

8q-(4q+4)-12=0

We get rid of parentheses

8q-4q-4-12=0

We add all the numbers together, and all the variables

4q-16=0

We move all terms containing q to the left, all other terms to the right

4q=16

q=16/4

q=4

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