5(4r+3)=37+7r

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Solution for 5(4r+3)=37+7r equation: 



5(4r+3)=37+7r

We move all terms to the left:

5(4r+3)-(37+7r)=0

We add all the numbers together, and all the variables

5(4r+3)-(7r+37)=0

We multiply parentheses

20r-(7r+37)+15=0

We get rid of parentheses

20r-7r-37+15=0

We add all the numbers together, and all the variables

13r-22=0

We move all terms containing r to the left, all other terms to the right

13r=22

r=22/13

r=1+9/13

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