5(4r+4)+5(2r+5)=195

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Solution for 5(4r+4)+5(2r+5)=195 equation: 



5(4r+4)+5(2r+5)=195

We move all terms to the left:

5(4r+4)+5(2r+5)-(195)=0

We multiply parentheses

20r+10r+20+25-195=0

We add all the numbers together, and all the variables

30r-150=0

We move all terms containing r to the left, all other terms to the right

30r=150

r=150/30

r=5

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