5(4r-2)+10=6(r+14)

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Solution for 5(4r-2)+10=6(r+14) equation: 



5(4r-2)+10=6(r+14)

We move all terms to the left:

5(4r-2)+10-(6(r+14))=0

We multiply parentheses

20r-(6(r+14))-10+10=0



We calculate terms in parentheses: -(6(r+14)), so:

6(r+14)

We multiply parentheses

6r+84

Back to the equation:

-(6r+84)



We add all the numbers together, and all the variables

20r-(6r+84)=0

We get rid of parentheses

20r-6r-84=0

We add all the numbers together, and all the variables

14r-84=0

We move all terms containing r to the left, all other terms to the right

14r=84

r=84/14

r=6

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