5(4t+3)=4(7t-5)

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Solution for 5(4t+3)=4(7t-5) equation: 



5(4t+3)=4(7t-5)

We move all terms to the left:

5(4t+3)-(4(7t-5))=0

We multiply parentheses

20t-(4(7t-5))+15=0



We calculate terms in parentheses: -(4(7t-5)), so:

4(7t-5)

We multiply parentheses

28t-20

Back to the equation:

-(28t-20)



We get rid of parentheses

20t-28t+20+15=0

We add all the numbers together, and all the variables

-8t+35=0

We move all terms containing t to the left, all other terms to the right

-8t=-35

t=-35/-8

t=4+3/8

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