5(4t+3)=4(7t-5)+3(9-2t)

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Solution for 5(4t+3)=4(7t-5)+3(9-2t) equation: 



5(4t+3)=4(7t-5)+3(9-2t)

We move all terms to the left:

5(4t+3)-(4(7t-5)+3(9-2t))=0

We add all the numbers together, and all the variables

5(4t+3)-(4(7t-5)+3(-2t+9))=0

We multiply parentheses

20t-(4(7t-5)+3(-2t+9))+15=0



We calculate terms in parentheses: -(4(7t-5)+3(-2t+9)), so:

4(7t-5)+3(-2t+9)

We multiply parentheses

28t-6t-20+27

We add all the numbers together, and all the variables

22t+7

Back to the equation:

-(22t+7)



We get rid of parentheses

20t-22t-7+15=0

We add all the numbers together, and all the variables

-2t+8=0

We move all terms containing t to the left, all other terms to the right

-2t=-8

t=-8/-2

t=+4

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