5(4t-5)-20(t-1)=-t-5(t+7)

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Solution for 5(4t-5)-20(t-1)=-t-5(t+7) equation: 



5(4t-5)-20(t-1)=-t-5(t+7)

We move all terms to the left:

5(4t-5)-20(t-1)-(-t-5(t+7))=0

We multiply parentheses

20t-20t-(-t-5(t+7))-25+20=0



We calculate terms in parentheses: -(-t-5(t+7)), so:

-t-5(t+7)

We add all the numbers together, and all the variables

-1t-5(t+7)

We multiply parentheses

-1t-5t-35

We add all the numbers together, and all the variables

-6t-35

Back to the equation:

-(-6t-35)



We add all the numbers together, and all the variables

-(-6t-35)-5=0

We get rid of parentheses

6t+35-5=0

We add all the numbers together, and all the variables

6t+30=0

We move all terms containing t to the left, all other terms to the right

6t=-30

t=-30/6

t=-5

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